Two bulbs are rated 60 W, 220 V and 60 W, 110 V respectively. Calculate the ratio of their Show
Given,Voltage, `V_1` = 220 v `V_2` = 110 v Power, `P_1 = P_2 = p = 60 w` As R= `V^2/P` `R_1` = `(V_1^2)/P = ((220 xx220))/60` `R_2` = `(V_2^2)/P = ((110xx110))/6` On dividing `R_1` and `R_2` `R_1/R_2 =(((220xx220))/60)/(((110xx110))/60) =4/1` ∴ `R_1 : R_2 =4:1` Concept: Electrical Power Is there an error in this question or solution?
Answer (Detailed Solution Below) Option 3 : 2 : 3
Concept: Electric Power:
If the Potential difference is constant, Power is inversely proportional to resistance. or Power × Resistance is constant Calculation: Now, Power of resistance 1 (R1) = P1 = 60 W Now, Power of resistance 2 (R2) = P2 = 40 W Now, P1 R1 = P2. R2 So, the required ratio is 2 : 3 Additional Information The power in terms of current and resistance is given as P = I 2 R I is current So, If the current would have been constant, the power would have been directly proportional to resistance. India’s #1 Learning Platform Start Complete Exam Preparation
Video Lessons & PDF Notes Trusted by 2,91,03,943+ Students > Solution Given For Bulb A: power = 100W voltage = 220V (adsbygoogle = window.adsbygoogle || []).push({}); We know that, P = V² / R R = V² / P = ( 220)² / 100 = 484 ohms.. For Bulb B: power = 60W Voltage = 220V R = V² / P = (220 )² / 60 = 2420 / 6 = 806.66 ohm... Therefore, the bulb B has greater resistance.
If two electric bulbs have 40 W and 60 W ratings at 220 V, then the ratio of their resistances will be Options(a) (3:2) (b) (2:3) (c) (3:4) (d) (4:3) Correct Answer:(3:2) Explanation:P = V² / R ⇒ R₁ / R₂ = P₂ / P₁ = 60 / 40 = 3 / 2 = 3 : 2 Related Questions: |
Two bulbs are rated 60w 220v and 40w 220v theratio of their resistances will be
Pos Terkait
Copyright © 2024 ketiadaan Inc.
