In how many ways can a team of 10 basketball players be chosen from 12 players?

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How many ways are there to select the starting 5 basketball players from a pool of 15 men who can play all of the positions?
How many ways are there to select five players from 10 players?
How many ways can you split 12 players into two teams of 6 players each?
How many ways can you split 10 players into two teams of 5 players each?
How many ways can 5 basketball players be chosen from a group of 9 players?
How many ways can a team of 5 players be chosen from a group of 15 students?
How many different combinations are possible if 3 players are selected from a team of 9?

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This is a permutation and combination problem. I'll Give you the answer, but you need to read about these two subjects. Permutation Part Now we have 10 players and want to make groupings of 5 people. It's harder to list all those permutations. To find the number of five-people permutations that we can make from 10 people without repeated (10_P_5), we'd like to have a formula because there are 30,240 such permutations and we don't want to write them all out! For five-people permutations, there are 10 possibilities for the first person, 9 for the second, 8 for the third, and 7 for the fourth, and 6 for the last person. We can find the total number of different five-people permutations by multiplying 10 x 9 x 8 x 7 x 6 = 30,240. This is part of a factorial To arrive at 10 x 9 x 8 x 7 x 6, we need to divide 10 factorial (10 because there are ten objects) by (10-5) factorial (subtracting from the total number of objects from which we're choosing the number of objects in each permutation). You can see below that we can divide the numerator by 5 x 4 x 3 x 2 x 1:

10_P_5 =

Combination Part we have 10 people from which we wish to choose 5 and we want to find the number of combinations of size 5 without repeated people that can be made from the ten people. To calculate 10_C_5, which is 120, we don't want to have to write all the combinations out! Since we already know that 10_P_5 = 30,240, we can use this information to find 10_C_5. Let's think about how we got that answer of 30240. We found all the possible combinations of 5 that can be taken from 10 (10_C_5). Then we found all the ways that five people in those groups of size 5 can be arranged: 5 x 4 x 3 x 2 x 1 = 5! = 120. Thus the total number of permutations of size 5 taken from a set of size 10 is equal to 5! times the total number of combinations of size 5 taken from a set of size 10: 10_P_5 = 5! x 10_C_5. When we divide both sides of this equation by 5! we see that the total number of combinations of size 5 taken from a set of size 10 is equal to the number of permutations of size 5 taken from a set of size 10 divided by 5!. This makes it possible to write a formula for finding 10_C_5:

10_C_5 =

So the answer is: You can have 252 starting teams of five from a group of 10 players.

pa Help po please, brainly kodin makasagot nito ^^

The product of -14.9 is -136.true or False?

the product of p and Q divided by 3

the sum of b and two less than the square of b

the square of m added to twice the number a

11 times nine times 8. 792. And so there are 792 different ways that we could select.

You asked, how many ways can a team of 5 basketball players be selected from 12 people? There are 12 people on a basketball team, and the coach needs to choose 5 to put into a game. a. How many different possible ways can the coach choose a team of 5 players? 12C2 = 792 ways the coach can choose a team of 5.

Amazingly, how many groups of 5 basketball players can be selected from a team of 10 players? There are 252 ways to select a committee of five members from a group of 10 people.

Best answer for this question, how many ways can a basketball team of 5 players be chosen from 8 players *? We have to select 5 players from (8 – 1) = 7 players. ∴ The required number of ways is 21.

Frequent question, how many teams of 7 players can be selected from a squad 10? (7!) = 10 · 9 · 8 7! 5 · 2 · 3 · 3 · 8 120 combinations available from 10 players.

10*9*8*7 = 5040. So there is 5040 ways to pick 4 people from a starting pool of 10.

Answer: 5! (5*4*3*2*1). So we will need to divide 6,375,600 by 5! Thus, we come up with the number 53,130.

The number of ways in which 5 basketball players can be selected from 8 basketball players is 8C5=56 8 C 5 = 56 . Using the product rule, the total number of ways in which both these selections can be made is 330∗56=18480 330 ∗ 56 = 18480 .