What will be the molarity of a solution which contains 5.85 gram of sodium chloride per 500 ml?

Question

What will be the molarity of a solution, which contains 5.85 g of NaCl(s) per 500 mL? (i) 4 mol L-1 (ii) 20 molL-1 (iii) 0.2 molL-1 (iv) 2molL-1

Correct Answer: (iii) 0.2 molL-1

Explanation: The Molarity is defined as the number of moles per volume of the solution in litres.

Given,

Mass = 5.85g

Molar mass = 58.5 g/mol

Volume of the solution = 0.5 L

So,

Number of moles = mass/molar mass

Number of moles =5.85/58.5

Number of moles =0.1 mol

Hence,

Molarity = 0.1/0.5

Molarity = 0.2mol/L

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Hello student,

The formula for molarity $M$ is

$M$ $=$ $\frac{mol}{v}$

The moles of sodium chloride is $\frac{5.85}{58.4} \approx 0.1$ $mol$

The volume of water is $0.5$ $l$

So

$M$ $=$ $\frac{mol}{v} = \frac{0.1}{0.5} = 0.2$ $M$

$Cheers!$

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