> Suggest Corrections 0 What temperature would be necessary to double the volume of a gas initially at s.t.p. if the pressure is decreased by 50%? P1 = 1 atm P2 = `1 xx 50/100 = 1/2` atm V1 = x cc V2 = 2x cc T1 = 273 K T2 = ? Using gas equation `("P"_1"V"_1)/"T"_1 = ("P"_2"V"_2)/"T"_2` ∴ T2 = `("P"_2"V"_2"T"_1)/("P"_1"V"_1)` `"T"_2 = 1/2 xx (2"x" xx 273)/(1 xx "x") = 273` K T1 = 273 - 273 = 0°C Concept: Standard Temperature Pressure (S.T.P.) Is there an error in this question or solution? |