What must be added in 4x⁴ 2x³ 6x² x - 5 so that the result is exactly divisible by 2x² x - 1

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CBSE 10 - Maths

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What must be added in 4x⁴ 2x³ 6x² x - 5 so that the result is exactly divisible by 2x² x - 1

Asked by navneetpra499 | 19 Jul, 2022, 05:06: AM

What must be added in 4x⁴ 2x³ 6x² x - 5 so that the result is exactly divisible by 2x² x - 1
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CBSE 10 - Maths

Asked by ravindar.sanka123 | 07 Jul, 2022, 01:30: PM

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CBSE 10 - Maths

Asked by babadubey9771 | 03 Jul, 2022, 10:53: AM

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CBSE 10 - Maths

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What must be added in 4x⁴ 2x³ 6x² x - 5 so that the result is exactly divisible by 2x² x - 1

Asked by anuragtikekar2006 | 07 May, 2022, 06:33: PM

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CBSE 10 - Maths

Asked by harshkumar128198k | 29 Mar, 2022, 04:19: PM

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We know that,

f(x) = g(x) x q(x) + r(x)

f(x) - r(x) = g(x) x q(x)

f(x) + {- r(x)} = g(x) x q(x)

Clearly , Right hand side is divisible by g(x).

Therefore, Left hand side is also divisible by g(x).Thus, if we add - r(x) to f(x), then the resulting polynomial is divisible by g(x).

Let us now find the remainder when f(x) is divided by g(x).

What must be added in 4x⁴ 2x³ 6x² x - 5 so that the result is exactly divisible by 2x² x - 1

Hence, we should add - r(x) = x - 2 to f(x) so that the resulting polynomial is divisible by g(x).


Page 2

We know that Dividend = Quotient x Divisor + Remainder.

Dividend - Remainder = Quotient x Divisor.

Clearly, Right hand side of the above result is divisible by the divisor.

Therefore, left hand side is also divisible by the divisor.

Thus, if we subtract remainder from the dividend, then it will be exactly divisible by the divisor.

Dividing x4 + 2x3 − 13x2 − 12x + 21 by x2 − 4x + 3

What must be added in 4x⁴ 2x³ 6x² x - 5 so that the result is exactly divisible by 2x² x - 1

Therefore, quotient = x2 + 6x + 8 and remainder = (2x - 3).

Thus, if we subtract the remainder 2x - 3 from x4 + 2x3 − 13x2 − 12x + 21 it will be divisible by x2 − 4x + 3.