Find the least 4 digit number which when divided by 3, 4 or 5 leaves a remainder of 2 in each case

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UPSC IAS Cadre allocation list released. Candidates can check the cadre allocated to them by referring to the same. Earlier, the UPSC Examinations 2021 Reserved List was released. 63 candidates have been recommended by the commission to fill in the remaining posts. With reference to the 2022 exam cycle, The Union Public Service Commission (UPSC) examination was conducted on the 16th, 17th, 18th, 24th, and 25th of September 2022. This is one of the most coveted jobs in India. The candidates are required to go through a 3 stage selection process - Prelims, Main and Interview. The marks of the main examination and interview will be taken into consideration while preparing the final merit list. The candidates must go through the UPSC Civil Service mains strategy to have an edge over others.

15

Q:

Answer:   D) 1022

Explanation:

Lowest 4-digit number is 1000.LCM of 3, 4 and 5 is 60.Dividing 1000 by 60, we get the remainder 40. Thus, the lowest 4-digit number that exactly divisible by 3, 4 and 5 is 1000 + (60 - 40) = 1020.

Now, add the remainder 2 that's required. Thus, the answer is 1022.