What three consecutive integers have a sum of 42? 3X + 3 = 42 3X + 3 - 3 = 42 - 33X = 39 3X/3 = 39/3X = 13 Which means that the first number is 13, the second number is 13 + 1 and the third number is 13 + 2. Therefore, three consecutive integers that add up to 42 are 13, 14, and 15.13 + 14 + 15 = 42 We know our answer is correct because 13 + 14 + 15 equals 42 as displayed above.Three Consecutive Integers Enter another number below to find what three consecutive integers add up to its sum. What three consecutive integers have a sum of 43? Here is the next algebra problem we solved.Copyright | Privacy Policy | Disclaimer | Contact
(a) 12, 13 and 14. (b) 12, 14 and 16. (c) 13, 14 and 15. (d) 13, 15 and 17
(b) Explanation: Let the smallest even whole number = x, Therefore, the next even whole number = (x + 2) And the third even whole number = x + 2 + 2 = x + 4 Now, x + (x + 2) + (x + 4) = 42 3x + 6 = 42 x = 12 Therefore numbers are 12, 14 and 16. 1 Expert Answer We can call the lowest integer x, the next integer x+2 (since our integers need to be even) and the third integer x+4. Now we can set up an algebraic equation. 42=x+(x+2)+(x+4). Combine like terms on the right side, Subtract 6 from each side x=12, which is our lowest integer. The next two integers we find with 12+2=14 and 12+4=16. Or just simply take the next two even integers. Thus, 12+14+16=42. |