How much power is consumed by a 240 ω light bulb when the current through it is 0.50 a?

In order to continue enjoying our site, we ask that you confirm your identity as a human. Thank you very much for your cooperation.

An electric bulb is connected to a 220 V generator the current is 0.50A What is the power of the bulb?

Open in App

Suggest Corrections

11

Please provide any 2 values and click "Calculate" to get the other values in the ohm's law equations V = I × R and P = V × I.

     
How much power is consumed by a 240 ω light bulb when the current through it is 0.50 a?


Related:resistor calculator


Ohm's Law

Ohm's Law states that the current through a conductor between two points is directly proportional to the voltage. This is true for many materials, over a wide range of voltages and currents, and the resistance and conductance of electronic components made from these materials remain constant. Ohm's Law is true for circuits that contain only resistive elements (no capacitors or inductors), regardless of whether the driving voltage or current is constant (DC) or time-varying (AC). It can be expressed using a number of equations, usually all three together, as shown below.

Where:

V is voltage in Volts R is resistance in Ohms

I is current in Amperes

Electrical Power

Power is the rate at which electrical energy is transferred by an electric circuit per unit time typically expressed in the SI (International System of Units) unit of Watts. Power is typically produced by electric generators and supplied to businesses and homes through the electric power industry, but can also be supplied by electric batteries or other sources.

In resistive circuits, Joule's Law can be combined with Ohm's Law to produce alternative expressions for the amount of power dissipated, as shown below.

P = V × I
P =
P = I2 × R

Where:

P is power in Watts

Ohm's Law Formula Wheel

Below is a formula wheel for Ohm's Law relationships between P, I, V, and R. This is essentially what the calculator does, and is just a representation of the algebraic manipulation of the equations above. To use the wheel, choose the variable to solve for in the middle of the wheel, then use the relationship for the two known variables within the cross section of the circle.

How much power is consumed by a 240 ω light bulb when the current through it is 0.50 a?