What point on x-axis is at a distance of 5 units?

Q: Find all points on the x-axis that are 5 units from the point (4,-3) A: We want to find all x such that the distance between the points (x, 0) and (4, -3) is equal to 5.

The points on the x-axis are (0, 0) and (8, 0).

Write the equation of the line parallel to the X-axis at a distance of 5 units from it and below the X-axis.

The equation of the line parallel to X-axis at a distance of 5 units from it and below the X-axis is y = −5.

Concept: Equations of Lines Parallel to the X-axis and Y-axis

  Is there an error in this question or solution?

Find points on the x-axis, which are at a distance of 5 units from the point A(5,-3).

Asked by Topperlearning User | 21 Nov, 2013, 02:03: AM

Let the required point on x-axis be (x, 0).

Using distance formula, we have:

(x - 5)2 + (0 + 3)2 = (5)2

(x - 5)2 = 25 - 9 =

x - 5 =

Answered by | 21 Nov, 2013, 04:03: AM

The points on the x axis which is are at a distance of 5 units from the point 6, 3, is areA. 2,0B. 10,0C. 3,0D. 5,0

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