 Text Solution Solution : The slope of the line making an angle `(2π)/3` with the positive x-axis is `m=tan{ (2pi)/3}` <br> `=- sqrt3` <br> Now, the equation of the line passing through point (0,2) and having a slope − 3 is `(y−2)=−sqrt3(x−0)` <br> `y−2=− 3x` <br> i.e; `3x+y−2=0` <br> The slope of line parallel to line `3x+y−2=0` is − 3 <br> It is given that the line parallel to line `3x+y−2=0` crosses the y-axis 2 units below the origin i.e; it passes through point (0,−2) <br> Hence, the equation of the line passing point (0,−2) and having a slope `−3` is `P:y−(−2)=−sqrt 3(x−0)` <br> ⇒`y+2=− sqrt3 x` <br> `⇒ sqrt3x+y+2=0` No worries! We‘ve got your back. Try BYJU‘S free classes today! No worries! We‘ve got your back. Try BYJU‘S free classes today! No worries! We‘ve got your back. Try BYJU‘S free classes today! Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses Open in App Suggest Corrections No worries! We‘ve got your back. Try BYJU‘S free classes today! No worries! We‘ve got your back. Try BYJU‘S free classes today! Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses No worries! We‘ve got your back. Try BYJU‘S free classes today! Open in App Suggest Corrections 1 |
What is the equation of a line parallel to x-axis and at a distance of 7 units below the origin?
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