What is the empirical formula for a compound that is 40% carbon 6.70% hydrogen and 53.3% oxygen hint *( remember to assume 100 g sample?

Chemistry

JAMB 2015

• A. CH2O
• B. C3H6O3
• C. C6H12O6
• D. C6H12O3

C = 40%, 40/12 = 3.33 H = 6.7%, 6.7/1 = 6.7 O = 53.3%, 53.3/16 = 3.33 C = 3.33/3.33 = 1 H = 6.7/3.33 = 2 O = 3.33/3.33 = 1 (CH2O)n = 180 (12 + 2 + 16)n = 180 30n = 180 n = 6

= C6H12O6

There is an explanation video available below.

Explanation Video