The concentration would be 0.76 mol/L. The most common way to solve this problem is to use the formula #c_1V_1 = c_2V_2# In your problem, #c_1# = 4.2 mol/L; #V_1# = 45.0 mL #c_2 = c_1 × V_1/V_2# = 4.2 mol/L × #(45.0"mL")/(250"mL")# = 0.76 mol/L This makes sense. You are increasing the volume by a factor of about 6, so the concentration should be about ¹/₆ of the original (¹/₆ × 4.2 = 0.7).
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University of Houston
Debra W. Algebra 4 months, 2 weeks ago
Answer: The concentration of a solution that contains 45 ml of alchohol per 135 ml of solution is 49%/100% |