The concentration would be 0.76 mol/L. The most common way to solve this problem is to use the formula #c_1V_1 = c_2V_2# In your problem, #c_1# = 4.2 mol/L; #V_1# = 45.0 mL #c_2 = c_1 × V_1/V_2# = 4.2 mol/L × #(45.0"mL")/(250"mL")# = 0.76 mol/L This makes sense. You are increasing the volume by a factor of about 6, so the concentration should be about ¹/₆ of the original (¹/₆ × 4.2 = 0.7).
The concentration would be 0.76 mol/L. The most common way to solve this problem is to use the formula #c_1V_1 = c_2V_2# In your problem, #c_1# = 4.2 mol/L; #V_1# = 45.0 mL #c_2 = c_1 × V_1/V_2# = 4.2 mol/L × #(45.0"mL")/(250"mL")# = 0.76 mol/L This makes sense. You are increasing the volume by a factor of about 6, so the concentration should be about ¹/₆ of the original (¹/₆ × 4.2 = 0.7).
Joana S. asked • 03/14/21What is the concentration of a solution made by diluting 45 mL of 6.0 M HCl to a final volume of 750 mL? 1 Expert Answer Joana S. What is the concentration of a solution made by diluting 45 mL of 6.0 M HCl to a final volume of 750 mL? 1 Expert Answer |