One card is drawn from a well-shuffled deck of 52 cards. Find the probability of getting a face card. Total number of outcomes = 52 Let E2 be the event of getting a face card. Number of favourable outcomes = 12 ∴ P(getting a face card) = P(E2) = `("Number of outcomes favourable to" E_2)/"Number of all possible outcomes"` `= 12/52 = 3/13` Thus, the probability of getting a face card is `3/13`. Concept: Concept Or Properties of Probability Is there an error in this question or solution? Page 2One card is drawn from a well-shuffled deck of 52 cards. Find the probability of getting a red face card. Total number of outcomes = 52 Let E3 be the event of getting a red face card. Number of favourable outcomes = 6 ∴ P(getting a red face card) = P(E3) = `("Number of outcomes favourable to" E_3)/"Number of all possible outcomes"` `6/52 = 3/26` Thus, the probability of getting a red face card is `3/26`. Concept: Concept Or Properties of Probability Is there an error in this question or solution? Page 3One card is drawn from a well-shuffled deck of 52 cards. Find the probability of getting a queen of black suit. Total number of outcomes = 52 Let E4 be the event of getting a queen of black suit.Number of favourable outcomes = 2 ∴ P(getting a queen of black suit) = P(E4) = `("Number of outcomes favourable to" E_4)/"Number of all possible outcomes"` `=2/52 = 1/26` Thus, the probability of getting a queen of black suit is `1/26`. Concept: Concept Or Properties of Probability Is there an error in this question or solution? Page 4One card is drawn from a well-shuffled deck of 52 cards. Find the probability of getting a jack of hearts. Let E5 be the event of getting a jack of hearts.Number of favourable outcomes = 1 ∴ P(getting a jack of hearts) = P(E5) = `("Number of outcomes favourable to" E_5)/"Number of all possible outcomes"` `= 1/52` Thus, the probability of getting a jack of hearts is `1/52`. Concept: Concept Or Properties of Probability Is there an error in this question or solution? Page 5One card is drawn from a well-shuffled deck of 52 cards. Find the probability of getting a spade. Total number of outcomes = 52 Let E6 be the event of getting a spade. Number of favourable outcomes = 13 ∴ P(getting a spade) = P(E6) = `("Number of outcomes favourable to" E_6)/"Number of all possible outcomes"` `=13/52 = 1/4` Thus, the probability of getting a spade is `1/4`. Concept: Concept Or Properties of Probability Is there an error in this question or solution? Page 6A card is drawn at random form a well-shuffled deck of playing cards. Find the probability that the card drawn is a card of spades of an ace. Total number of all possible outcomes= 52 Number of spade cards = 13 Number of aces = 4 (including 1 of spade) Therefore, number of spade cards and aces = (13 + 4 − 1) = 16 ∴ P( getting a spade or an ace card) = `16/52 = 4/13` Concept: Concept Or Properties of Probability Is there an error in this question or solution? Page 7A card is drawn at random form a well-shuffled deck of playing cards. Find the probability that the card drawn is a red king. Total number of all possible outcomes= 52 Number of red kings = 2 ∴ P( getting a red king) =`2/52 = 1/26` Concept: Concept Or Properties of Probability Is there an error in this question or solution? Page 8A card is drawn at random form a well-shuffled deck of playing cards. Find the probability that the card drawn is either a king or a queen. Total number of all possible outcomes= 52 Total number of kings = 4 Total number of queens = 4 Let E be the event of getting either a king or a queen. Then, the favourable outcomes = 4 + 4 = 8 ∴ P( getting a king or a queen) = P (E) = `8/52 = 2/13` Concept: Concept Or Properties of Probability Is there an error in this question or solution? Page 9A card is drawn at random form a well-shuffled deck of playing cards. Find the probability that the card drawn is neither a king nor a queen. Let E be the event of getting either a king or a queen. Then, (not E) is the event that drawn card is neither a king nor a queen. Then, P(getting a king or a queen ) = `2/13` Now, P (E) + P (not E) = 1 ∴ P(getting neither a king nor a queen ) = `1 - (2/13) = 11/13` Concept: Concept Or Properties of Probability Is there an error in this question or solution? Uh-Oh! That’s all you get for now. We would love to personalise your learning journey. Sign Up to explore more. Sign Up or Login Skip for now Uh-Oh! That’s all you get for now. We would love to personalise your learning journey. Sign Up to explore more. Sign Up or Login Skip for now |