At what temperature is the root mean square speed of an atom in an argon gas cylinder equal to the r.m.s. speed of helium gas atom at –20°C? [Atomic mass of Ar = 39.9, He = 4.0]
R.M.S speed of atom is given by, v=3kTm = 3RTM ...(1) where m is mass of atom and M atomic mass. Here we have,Atomic mass of Argon, MAr=39.9, Atomic mass of Helium,
Temperature, THe =-20°C = 253K, Temperature of Argon gas, TAr=? Now usign equation (1), we have3RTHeMHe = 3RTArMAr TAr = THeMHeMAr = 253×39.94 =2.5×103K is the required temperature at which r.m.s speed of an argon gas cylinder is equal to the r.m.s speed of helium gas atom. Write Postulates of the kinetic theory of gases. Postulates of the kinetic theory of gases:
Concept: Kinetic Molecular Theory of Gases Is there an error in this question or solution? |