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Solution: When two dice are thrown simultaneously, the sample space of the experiment is {(1,1), (1,2), (1,3), (1,4), (1,5), (1,6), (2,1), (2,2), (2,3), (2,4), (2,5), (2,6), (3,1),(3,2), (3,3), (3,4), (3,5), (3,6), (4,1), (4,2), (4,3), (4,4), (4,5), (4,6), (5,1), (5,2), (5,3), (5,4), (5,5), (5,6), (6,1), (6,2), (6,3), (6,4), (6,5), (6,6)} So there are 36 equally likely outcomes. Possible number of outcomes = 36. (i)Let E be an event of getting a doublet. Favourable outcomes = {(1,1), (2,2),(3,3), (4,4), (5,5),(6,6)} Number of favourable outcomes = 6 P(E) = 6/36 = 1/6 Probability of getting a doublet is 1/6 . (ii)Let E be an event of getting a sum of 8. Favourable outcomes = {(2,6), (3,5), (4,4), (5,3), (6,2)} Number of favourable outcomes = 5 P(E) = 5/36 Probability of getting a sum of 8 is 5/36. |