Text Solution `2.3xx10^(-8)N``4.6xx10^(-8)N``1.5xx10^(-8)N`None of these Answer : A Solution : Change on electron `16xx10^(-19)C` <br> Using the relation, `F=(1)/(4pi epsilon_(0)).(q_(1)q_(2))/(r^(2))` <br> `"Here, "q_(1)=q_(2)=1.6xx10^(-19)C` <br> `r=1Å=10^(-10)m` <br> So, Force between the electrons <br> `F=(9xx10^(9)xx(1.6xx10^(-19))^(2))/((10^(-10))^(2))=2.3xx10^(-8)N` Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses No worries! We‘ve got your back. Try BYJU‘S free classes today! No worries! We‘ve got your back. Try BYJU‘S free classes today! No worries! We‘ve got your back. Try BYJU‘S free classes today! Open in App Suggest Corrections |