Two charges 2 microcoulomb and minus 2 microcoulomb are placed at points A and B 6 cm apart

Itabur Rahman 2019-06-28 17:49:42

Where is the figure??

Vishawjeet 2019-05-17 13:19:51

Where is the figure??

virendra veer chaturvedi 2016-08-10 19:53:04

niceee....

usha 2016-08-08 04:44:37

bad site

Page 2

Sangeetha 2019-06-25 05:28:31

This was really helpful.. Manish mannu has commented that the unit was given wrong here.. But actually it's correct.. Pls do check properly before commenting..

Manish mannu 2019-06-13 12:57:21

There is a minor mistake in 2nd solution. 9*10^9Nm^2/C^2

Poonamchand 2019-01-08 10:23:20

It can not be solved by using gauss law????

Priyas Kumar 2018-10-18 00:03:41

Thanku

Tuba Aqueel 2018-08-01 01:28:34

Tnk u so much for ur help

harsha 2018-05-09 13:08:25

It was very very helpful. Ty Saral studyðŸ˜ŠðŸ˜Š

rah 2018-03-30 15:42:20

nice

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Two charges 2 μC and −2 µC are placed at points A and B 6 cm apart.

(a) Identify an equipotential surface of the system.

(b) What is the direction of the electric field at every point on this surface?

(a) The situation is represented in the given figure.

An equipotential surface is a plane on which total potential is zero everywhere. This plane is normal to line AB. The plane is located at the mid-point of line AB because the magnitude of charges is the same.

(b) The direction of the electric field at every point on this surface is normal to the plane in the direction of AB.

Concept: Equipotential Surfaces

Is there an error in this question or solution?

Two charges 2 μ C and 2 μ C are placed at points A and B 6 cm apart.a Identify an equipotential surface of the system.b What is the direction of the electric field at every point on this surface?

A charge of 8 mC is located at the origin. Calculate the work done in taking a small charge of –2 x 10–9 C from a point P(0, 0, 3 cm) to a point Q(0, 4 cm, 0), via a point R (0, 6 cm, 9 cm).

Given charge q = 8 mC = 8 x 10–1 C is located at origin and the small charge (q0 = –2 x 10–9 C) is taken from point P (0, 0, 3 cm) to a point Q (0, 4, cm, 0) through point R (0, 6 cm, 9 cm) which is shown in the figure.
Initial separation between q0 and q is rp = 3 cm = 0.03 m
Final separation between q0 and q is rQ = 4 cm = 0.4 m

Work done in taking the charge q0 from point P to Q does not dependent on the path followed and depends only upon rp and rQ i.e., initial and final positions.

or,