Two electric bulbs A and B are marked 220 V, 40 W and 220 V, 60 W respectively. Which one of these bulbs has higher resistance?
Given, two electrical bulbs. P = V 2/R or R = V2/P i.e., R ∝ 1/P.Resistance is inversely proportional to power. Therefore, the first bulb having lesser power has higher resistance. Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses No worries! We‘ve got your back. Try BYJU‘S free classes today! No worries! We‘ve got your back. Try BYJU‘S free classes today! No worries! We‘ve got your back. Try BYJU‘S free classes today! Open in App Suggest Corrections 12 Open in App
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Concept: Electric Power:
If the Potential difference is constant, Power is inversely proportional to resistance. or Power × Resistance is constant Calculation: Now, Power of resistance 1 (R1) = P1 = 60 W Now, Power of resistance 2 (R2) = P2 = 40 W Now, P1 R1 = P2. R2 So, the required ratio is 2 : 3 Additional Information The power in terms of current and resistance is given as P = I 2 R I is current So, If the current would have been constant, the power would have been directly proportional to resistance. India’s #1 Learning Platform Start Complete Exam Preparation
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