Two bulbs of 40w and 60w are connected to 220v line, the ratio of resistance will be

Two electric bulbs A and B are marked 220 V, 40 W and 220 V, 60 W respectively. Which one of these bulbs has higher resistance?

Given, two electrical bulbs.
Potential across first bulb, V1= 220 V
Power of first bulb, P1= 40 W
Potential across second bulb, V2 = 220 V
Power of second bulb, P2 = 60 WNow,

P = V

2/R or R = V2

/P i.e., R ∝ 1/P.Resistance is inversely proportional to power.

Therefore, the first bulb having lesser power has higher resistance.

Two bulbs marked 'A' 60W, 220V & 'B' 100W, 220V are connected in parallel to 220 volt source. Which of the two will glow brighter?

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40 w and 60w of two bulb connected a line which have electric potential 220 volt then find the ratio of resistance

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Two bulbs of 40w and 60w are connected to 220v line, the ratio of resistance will be

Concept:

Electric Power:

  • The rate of consumption of electrical energy is called Electric power.
  • It is given as 

If the Potential difference is constant, Power is inversely proportional to resistance.

 or 

Power × Resistance is constant

Calculation:

Now, Power of resistance 1 (R1) = P1 = 60 W

Now, Power of resistance 2 (R2) = P2 = 40 W

Now, P1 R1 = P2. R2

So, the required ratio is 2 : 3

Additional Information

The power in terms of current and resistance is given as 

P = I 2 R

I is current

So, If the current would have been constant, the power would have been directly proportional to resistance.

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