Suppose that e and f are two events and that p(e and f) = 0.38 and p(e) = 0.8. what is p(e)

Sean N.

Intro Stats / AP Statistics 2 weeks, 1 day ago

Find the indicated probability If necessary round to three decimal places: Suppose that Eand F are two events and that P(E and F) = 0.38 and P(E) = 0.8 What is P(F E)? Find the value of the permutation. I0P 6 Provide an appropriate response: From names 0n ballot; committee of 5 will be elected to attend political national convention How many different committees are possible? Given the table of probabilities for the random variable does this form probability distribution? Answer Yes or No. If no, state why: PG) Q2 Q0Z 022 017

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Audrey F.

National University of Singapore

Find the indicated probability If necessary round to three decimal places: Suppose that Eand F are two events and that P(E and F) = 0.38 and P(E) = 0.8 What is P(F E)? Find the value of the permutation. I0P 6 Provide an appropriate response: From names 0n ballot; committee of 5 will be elected to attend political national convention How many different committees are possible? Given the table of probabilities for the random variable does this form probability distribution? Answer Yes or No. If no, state why: PG) Q2 Q0Z 022 017

In the first question, we are given probability: e and f is 0.38 non probability, is terms notations intersect or is plus set, notation is union, so probability e and f will be probability, e, intersect, f and probability a ser .8. Now we want to find conditional probability of f given e, so there is 1 to find a probability of f, given he has already occurred now using base theorem. This will be probability of f in the s over probability of e. Now, f, interset e is the same as e in the set. So is 0.38 and probability of a 0.8, so we will have 0.475 next. We want to find 10 p 6. That is 10 permutate, 6 now in general, if i have any distinct objects and i want to permutate r of them, it will be n factorial over n minus r factorial. So now my n is 10 point, so i have 10 factorial and my r is 6. So divided by 106 factorial and that will be 151200 now in the third question we are given that there are 9 names in a ballad, and a committee of 5 is to be elected. We want to find the number of different possible comedies now take note that these 9 names are selected without replacement. There are no repeats to a same person holding 2 ormopositions and that the, although selection, is not important because in this committee there are no different, distinct titles oppositions to slot or arrange these people into. So the order is not important. So without replacement order not important. We will be using combination, so if i have distinct objects- and i need to choose r of them- it will be n factorial over r factorial times n minus r factorial. So a number of different possible committees would be 9 choose 5, so that will be 9 factorial over 5 factorial times 9 minus 5 factorial, and that will be 126 point now. The last question we are given this probability table over here: does the random variable x form a probability distribution? Now it will if the sum of the probability were add up to 1. So, let's add up the sum of the probability, so that will be 0.02 when x goes 0 when x goes to 1. At this, when x equals to 2 you're .22, when x equals to 3, the probability .27 and when x is equal to 4. The probability is .42 and the probability is actually 1. So therefore, x forms a probability: distribution,

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Data And Variables

Data And Variables - Example 1

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Andrew E.

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