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Solve the quadratic equation x2 - 3(x + 3) = 0; Give your answer correct two significant figures
x2 - 3(x + 3) = 0
`=> x^2 - 3x - 9 = 0`
Comparing with `ax^2 + by + c` we get
`:. x = (-b+-sqrt(b^2 - 4ac))/(2a)`
`=> x = (-(-3)+- sqrt((-3)^2 - 4(1)(-9)))/(2(1))`
`=> x = (3+- sqrt(9+36))/2`
`=> x = (3+- sqrt45)/2`
`=> x = (3+- sqrt(9xx5))/2`
`=> x = (3+-3sqrt5)/2`
`=> x = (3+3sqrt5)/2 or x = (3-3sqrt5)/2`
`=> x = (3+3xx2.236)/2 or x = (3-3xx2.236)/2`
`=> x = (3+6.708)/2 or x = (3-6.708)/2`
`=> x = 9.708/2 or x = (-3.708)/2`
`=>` x = 4.85 or x = -1.85
`=>` x = 4.9 or x = -1.9
Concept: Quadratic Equations
Is there an error in this question or solution?