The specific part of the date or time value (year, month, or day, hour, minute, second, millisecond, or microsecond) that the function operates on. For more information, see Date parts for date or timestamp functions. Show Specifically, DATEDIFF determines the number of date part boundaries that are crossed between two expressions. For example, suppose that you're calculating the difference in years between two dates, 1 and 2. In this case, the function returns 1 year despite the fact that these dates are only one day apart. If you are finding the difference in hours between two timestamps, 3 and 4, the result is 2 hours. If you are finding the difference in hours between two timestamps, 5 and 6, the result is 2 hours.date|time|timetz|timestampA DATE, TIME, TIMETZ, or TIMESTAMP column or expressions that implicitly convert to a DATE, TIME, TIMETZ, or TIMESTAMP. The expressions must both contain the specified date or time part. If the second date or time is later than the first date or time, the result is positive. If the second date or time is earlier than the first date or time, the result is negative. BIGINT The following example finds the differences in number of hours, between a TIMETZ literal and timetz_val. There are different methods for checking the number of days, hours, and seconds that are commonly used to provide information related to data. Since you can’t manually change the count of the years and months, we follow some simple tricks to get the number in JavaScript. Using the Date getTime() MethodIn JavaScript, we use different methods to calculate the days, hours, and seconds. Most popular way to calculate the time is .getTime(). However, you will get the result in milliseconds and have to convert it into seconds through division. Syntaxvar x = new Date("Aug 12, 2022 19:45:25"); var y = new Date("Aug 14, 2022 19:45:25"); let seconds = Math.abs(x.getTime() - y.getTime())/1000; Here x and y are two dates. We will use the getTime() to get the times in milliseconds of both dates. We take the absolute difference between the two times in milliseconds. Then, after subtracting the time in milliseconds, we will divide it by 1000. Algorithm
Example 1We have created both the dates manually using the new Date(). You can also use different methods to generate the date in JavaScript.
Using the Math.abs() MethodMath.abs() is a method used to round the numbers to the nearest answer to avoid getting floating numbers. Hence, you can also use Math.round() method instead of Math.abs(). You can get the time difference using this method in milliseconds. The time can be converted in seconds by dividing the output by 1000. SyntaxWe will use the following syntax to get the time in milliseconds and convert it into seconds through the division method let x = new Date(); let y = new Date(); let dif = Math.abs(x - y) / 1000; Here, we find the number of seconds between two dates – x and y. We take the absolute difference between these two dates using the Math.abs() method. This difference is in milliseconds, so we divide by 1000 to convert it into seconds. Example 2In this example, there are more than 31 days of difference in both the dates. We kept the dates similar so that the output could also be checked in seconds manually.
The methods like .getTime() and Math.abs() are commonly used in JavaScript. You can alternatively use the Math.round() method to get similar output. Have a look at the below example. Example 3
While getting the answers, you should ensure the time is converted in seconds because the output can also be in minutes or milliseconds. Hence, you can check the examples above to understand the best way to get the output in seconds. |