How many different selections of 5 books can be made from 12 different books if I two particular books are always selected ii two particular books are never selected?

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How many different selections of 5 books can be made from 12 different books if, Two particular books are never selected?

Two particular books are never selected.

Since two books are never selected.

The total number of books is 10.

∴ The number of ways of selecting 5 books from 10 books

= 10C5

= `(10!)/(5! xx (10 - 5)!)`

= `(10!)/(5! xx 5!)`

= `(10 xx 9 xx 8 xx 7 xx 6 xx 5!)/(5! xx 5!)`

= `(10 xx 9 xx 8 xx 7 xx 6)/(5!)`

= `(10 xx 9 xx 8 xx 7 xx 6)/(5 xx 4 xx 3 xx 2 xx 1)`

= 2 × 9 × 2 × 7

= 252 ways

  Is there an error in this question or solution?

How many different selections of 5 books can be made from 12 different books if, Two particular books are always selected?

Total number of books = 12

Number of books to be selected = 5

Given Two books are always selected.

Remaining number of books to be selected = 3

The number of ways of selecting the remaining 3 books from the remaining 10 books = 10C3 

= `(10!)/(3! xx (10 - 3)!)`

= `(10!)/(3! xx 7!)`

= `(10 xx 9 xx 8 xx 7!)/(3! xx 7!)`

= `(10 xx 9 xx 8)/(3!)`

= `(10 xx 9 xx 8)/(3 xx 2 xx 1)`

= 5 × 3 × 8

= 120 ways

  Is there an error in this question or solution?


Page 2

How many different selections of 5 books can be made from 12 different books if, Two particular books are never selected?

Two particular books are never selected.

Since two books are never selected.

The total number of books is 10.

∴ The number of ways of selecting 5 books from 10 books

= 10C5

= `(10!)/(5! xx (10 - 5)!)`

= `(10!)/(5! xx 5!)`

= `(10 xx 9 xx 8 xx 7 xx 6 xx 5!)/(5! xx 5!)`

= `(10 xx 9 xx 8 xx 7 xx 6)/(5!)`

= `(10 xx 9 xx 8 xx 7 xx 6)/(5 xx 4 xx 3 xx 2 xx 1)`

= 2 × 9 × 2 × 7

= 252 ways

  Is there an error in this question or solution?