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Given, ⇒ A × 1/6 = B × 1/2 ⇒ A = 3B ⇒ \(\frac{A}{B} = \frac{3}{1}\) ∴ A’s efficiency = 3 unit / day. & B’s efficiency = 1 unit / day. According to Qs. (A + B) Complete in 10 day ∴ Total Work = (3 + 1) × 10 = 4 × 10 = 40 ∴ Time taken by \(A = \frac{{40}}{{3}}\) = 13.33 Days = 13 Days. India’s #1 Learning Platform Start Complete Exam Preparation
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Mock Tests & Quizzes Trusted by 3.3 Crore+ Students Description for Correct answer: \( \Large A:B \)time \( \Large 3:1 \)eff. \( \Large 1:2 \)We have to do time equal so, Both do the work in 18 days So, total work = \( \Large \left( A + B\right) 's eff. \times 18 \) = \( \Large \left( 4 + 6\right) \times 18 \) = 180 units. B will complete the work in=\( \Large \frac{180}{6} =30\) days Part of solved Time and work questions and answers : >> Aptitude >> Time and work Comments Similar Questions |