Open in App Suggest Corrections 0 Let the two parts be x and y.From the given information,x + y = 20 ⇒ y = 20 – x 3x2 = (20 – x) + 10 3x2 = 30 – x 3x2 + x – 30 = 0 3x2 – 9x + 10x – 30 = 03x(x – 3) + 10(x – 3) = 0(x – 3) (3x + 10) = 0x = 3, -10/3Since, x cannot be equal to -10/3, so, x = 3. Thus, one part is 3 and other part is 20 – 3 = 17. |
Divide 20 into two parts such that three times the square of one part exceeds the other part by 10
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