Compare the time period of two pendulums of length 9m and 16m

Compare the time periods of the two pendulums of lengths 1 m and 9 m.

Let T1 and T2 be the time periods of the two pendulums of lengths 1m and 9m, respectively.

`T_1/T_2 = (2pisqrt(1/"g"))/(2pisqrt(9/"g"))`

or , `T_1/T_2 = sqrt(1/9)`

or , `T_1/T_2 = 1/3`

Concept: Simple Pendulum for Time

  Is there an error in this question or solution?

Text Solution

`3 : 4``9 : 16``16 : 9``4 : 3`

Answer : D

Solution : `T prop sqrtl, (T_(A))/(sqrt(l_(A))) = (T_(B))/(sqrt(l_(b))), (T_(A))/(T_(B)) = sqrt((l_(A))/(l_(B))) = sqrt((9)/(16)) = (3)/(4)` <br> `T_(A): T_(B) = 3 :4` But `(T_(1))/(T_(2)) = ((1)/(n_(1)))/((1)/(n_(2))) rArr (n)/(n2) = 4 :3`