An electric bulb is connected to a 220v generator the current is 0.05a what is the power of the bulb

An electric bulb is connected to a 220v generator the current is 0.05a what is the power of the bulb

Electric power can be expressed as the rate at which work is done or energy is transmitted in an electric circuit.  A given value of power can be generated by a value combination of current and voltage. In order to determine power of the bulb, we have to:

Step 1: Data Given

The following data is already mentioned:

  • Voltage, V = 220 V
  • Current, I = 0.05 A

Step 2: Finding Solution

Since the voltage and current of a bulb are already mentioned, power can be estimated via the derived formula of Power, which is:

Power = Voltage × Current

Thus,

⇒ p = 220 x 0.05p 

= 22 x 0.5p 

= 11 W

Therefore, the power which is required equals 11 W.

  1. In An Arrangement Of Resistances, Find Effective Resistance Between Points A and B.
  2. What Is Effective Resistance?
  3. Find The Highest And Lowest Total Resistance Of A Combination Of Four Coils With Resistances 4 Ohms, 8 Ohms, 12 Ohms, 24 Ohms.
  4. What is Null Voltage?
  5. Three Incandescent Bulbs (Each 100 W) Are Attached In Series. In Another Circuit, Three More Bulbs Of Same Wattage Are Attached Parallelly To An Equal Source.
  6. Two Identical Resistors With Resistances 15 Ohm Are Connected In Series And Parallel To A Battery Of 6 V. Calculate Ratio Of Power Consumed.
  7. For The Resistor Combination, Find The Equivalent Resistance Between M and N.
  8. A Circuit Consists Of A Battery Of 3 Cells (2 V Each), A Combination Of Three Resistors, 10 Ohm, 20 Ohm And 30 Ohm, Attached Parallelly, With Plug Key And Ammeter (In Series).
  9. X and Y, which are two resistors, with resistances of 2 Ω and 3 Ω respectively are first connected in parallel and then in series. In both cases, the voltage that is supplied is 5 V. (i) Illustrate a circuit diagram to show the combination of resistors. (ii) Calculate the amount of voltage across 3 Ω resistor in the series combination of resistors.
  10. Draw An Electric Circuit With A Cell, Key, Ammeter, A Resistor (Series) Of 2 Ohm With a Combination Of Two Resistors (4 Ohm Each) In Parallel And A Voltmeter Across Parallel Combination.

Do Check Out:

Here,   Ptential of the generator, V = 220 VCurrent flowing across the electric bulb, I = 0.50 ATherefore, Power of bulb, P = VI                          =  220 V x 0.50 A

                         = 110 W. 

An electric bulb is connected to a 220 V generator the current is 0.50A What is the power of the bulb?

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