3 light travels through water with a speed of 2.25 108 m s what is the refractive index of water

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The speed of light in water is 2.25 × 108 m/s. If the speed of light in vacuum be 3 × 108 m/s, calculate the refractive index of water.

Given:
Speed of light in water = 2.25 × 108 m/s
Speed of light in vacuum = 3 × 108 m/sRefractive index of water = ?Applying the formula for refractive index, we get:​Refractive index of a medium = (Speed of light in vacuum) / (Speed of light in the medium)For water:Refractive index of water = (Speed of light in vacuum) / (Speed of light in water)

= (3 × 108) / (2.25 × 108)

Thus, the refractive index of water is 1.33.

Concept: Refractive Index

  Is there an error in this question or solution?

Text Solution

1.411.471.331.5

Answer : C

Solution : Here, speed of light in water, `v = 2.25 xx 10^(8)m//s` <br> speed of light in vacuum, `c = 3 xx 10^(8)m//s`, refractive index, `n = ?` <br> From `n = c/v`, <br> `n = (3xx10^(8))/(2.25xx10^(8)) = 1.33`