What is the probability of drawing a king and a queen consecutively from a deck of 52 cards?

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The probability of getting drawing a king and queen from a deck of 52 cards without replacement is $\frac{4}{52} \frac{4}{51}$. I'm confused why it's not twice of this. We could achieve a king and queen in 2 different ways. First drawn card is a king and second drawn card is a queen, or first drawn card is a queen and second drawn card is a king. These are disjoint events, so wouldn't the probability actually be $\frac{4}{52} \frac{4}{51} + \frac{4}{52} \frac{4}{51}$?

I saw the first result left by the comment by tpb261 in Probability in cards that $4$ people each get queen and king?.

d)1/2Probability of getting a tail in one toss = 1/2The coin is tossed twice. So 1/2 * 1/2 = 1/4 is the answer.Here’s the verification of the above answer with the help of samplespace.When a coin is tossed twice, the sample space is {(H,H), (H,T), (T,H),(T,T)}.Our desired event is (T,T) whose occurrence is only once out of fourpossible outcomes and hence, our answer is 1/4.Q6A medical treatment has a success rate of .8. Twopatients will be treated with this treatment.Assuming the results are independent for the two patients, what is the probability that neither one ofthem will be successfully cured?