(a)4.43$\mathrm { m } / \mathrm { s } ^ { 2 }$
(b)53.7$\mathrm { N }$
(a)4.43$\mathrm { m } / \mathrm { s } ^ { 2 }$
(b)53.7$\mathrm { N }$
Page 2
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A tow truck pulls a car that is stuck in the mud, with a force of 2500 N as in Fig P5.27 The tow cable is under tension and therefor pulls downward and to the left on the pin at its upper end. The light pin is held in equilibrium by forces exerted by the two bars A and B. Each bar is a strut that is, each is a bar whose weight is small compared to the forces it exerts, and which exerts forces only through hinge pins at its ends. Each strut exerts a force directed parallel to its length. Determine the force of tension or compression in each strut. Proceed as follows Make a guess as to which way (pushing or pulling ) each force acts on the top pin Draw a free-body diagram of the pin. Use the condition for equilibrium of the pin to translate the free-body diagram into equations. From the equations calculate the forces exerted by struts A and B. If you obtain a positive answer, you correctly guessed the direction of the force. A negative answer means the direction should be reversed, but the absolute value correction should be reversed, but the absolute value correctly gives the magnitude of the force. If a strut pulls of a pin, it is in tension. If it pushes, the strut is in compression. Identify whether each strut is in tension or in compression.
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