What is the slope of any line perpendicular to 2y = 4x +3 ?
Explanation: First, we must solve the equation for y to determine the slope: y = 2x + 3/2 By looking at the coefficient in front of x, we know that the slope of this line has a value of 2. To fine the slope of any line perpendicular to this one, we take the negative reciprocal of it: slope = m , perpendicular slope = – 1/m slope = 2 , perpendicular slope = – 1/2
What line is perpendicular to 2x + y = 3 at (1,1)?
x – 2y = -1 Explanation: Find the slope of the given line. The perpendicular slope will be the opposite reciprocal of the original slope. Use the slope-intercept form (y = mx + b) and substitute in the given point and the new slope to find the intercept, b. Convert back to standard form of an equation: ax + by = c.
What is the slope of the line perpendicular to the line given by the equation 6x – 9y +14 = 0
Explanation: First rearrange the equation so that it is in slope-intercept form, resulting in y=2/3 x + 14/9. The slope of this line is 2/3, so the slope of the line perpendicular will have the opposite reciprocal as a slope, which is -3/2.
What is the slope of the line perpendicular to the line represented by the equation y = -2x+3?
Explanation: Perpendicular lines have slopes that are the opposite of the reciprocal of each other. In this case, the slope of the first line is -2. The reciprocal of -2 is -1/2, so the opposite of the reciprocal is therefore 1/2.
Find the slope of a line perpendicular to the line y = –3x – 4.
Explanation: First we must find the slope of the given line. The slope of y = –3x – 4 is –3. The slope of the perpendicular line is the negative reciprocal. This means you change the sign of the slope to its opposite: in this case to 3. Then find the reciprocal by switching the denominator and numerator to get 1/3; therefore the slope of the perpendicular line is 1/3.
What is the slope of a line perpendicular to the following:
Explanation: The question puts the line in point-slope form y – y1 = m(x – x1), where m is the slope. Therefore, the slope of the original line is 1/2. A line perpendicular to another has a slope that is the negative reciprocal of the slope of the other line. The negative reciprocal of the original line is –2, and is thus the slope of its perpendicular line.
A line is defined by the following equation: What is the slope of a line that is perpendicular to the line above?
Explanation: The equation of a line is where is the slope.Rearrange the equation to match this: For the perpendicular line, the slope is the negative reciprocal; therefore
Which of the following lines is perpendicular to the line passing through the points ?
Explanation: First, you must find the slope of the line given to you. Remember that the slope is calculated: Thus, for our data, this is: Now, the perpendicular slope to this is opposite and reciprocal. Hence, it must be . This only holds for the equationTo know this, solve the equation for the format . This will let you find the slope very quickly, for it is . First, add to both sides:Next, divide everything by :You really just need to pay attention to the term. This reduces to , which is just what you need!
What is the slope of a line that is perpendicular to the equation given by:
Explanation: Perependicular lines have slopes whose product is . and so the answer is
What is the slope of a line perpendicular to line , which runs through and ?
Explanation: To find the slope of a perpendicular line, we take the reciprocal of the known slope , where .The easy way to do this is to simply take the fraction (a whole slope can be made into a fraction by placing in the denominator), exchange the numerator and denominator, then multiply the fraction byHowever, if we attempt to follow this procedure, we get: , which is undefined.Thus, our perpendicular line (which is a vertical line) has an undefined slope.
Liban
Emory University, Bachelor of Science, Mathematics/Economics.
Yvan
Brigham Young University-Provo, Bachelor of Science, Mathematics Teacher Education.
Sam
University of Essex, Bachelor of Science, Telecommunications Technology. University of Hertfordshire, Master of Science, Comp...
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