Answer VerifiedHint: The refractive index of a substance is a dimensionless number that describes how fast light passes through a substance. It is defined as the ratio of c is the speed of light in a vacuum and v is the phase speed of light in the medium. Complete step by step solution: Given thatrefractive index for flint glass with respect to air $\mu _1 = 1.65$refractive index for alcohol with respect to air $\mu _2 = 1.36$now refractive index of glass with respect to alcohol $\mu _3$. $\Rightarrow$ ${\mu _3 = }\dfrac{{{{\mu _1}}}}{{{\mu _2}}}$ $\Rightarrow$ ${{\mu _3 = }}\dfrac{{{\text{1}}{\text{.65}}}}{{1.36}}$ $\therefore {{ \mu _3 = 1}}{\text{.21}} $Thus, the refractive index of dense flint glass with respect to alcohol $\mu _3$ is equal to 1.21.Additional Information: Refractive index, also called index of refraction, is the measurement of the bending of a beam of light while passing from one medium to another. If i is the angle of incidence of the ray in a vacuum, and r is the angle of refraction, and refractive index is defined as the ratio of the sine of the angle of incidence of the sine of the angle of refraction. $i.e.,{\text{ refractive index n = }}\dfrac{{\sin {\text{ i}}}}{{\sin {\text{ r}}}}$The refractive index is equal to the speed of light c of a given wave in empty space divided by its velocity in the material$ or,{\text{ n = }}\dfrac{c}{v}$Note: The refractive index of a medium is the ratio of the speed of light in a vacuum to the speed of light in the medium, therefore it has no unit, and is unitless. The refractive index of a medium is (to some extent) dependent on the frequency of light, with the highest value being n with the highest frequencies.
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Given Refractive index = n = 1.65 Using,Refractive Index= speed of light in vaccum/ speed of light in glass 1.65 = 3*108 ms-1 / speed of light in glass Therefore speed of light in glass is 1.8 *108 ms-1 HOPE THIS HELPS!!!!!!!!!
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