Draw a line segment of length 6 cm and divide it in the ratio of .measure the two parts

Question 2 Constructions Exercise 9A

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Answer:

(i) Steps of construction:

1. Draw a line segment AB = 8 cm.
2. Draw a ray AX making an acute angle at A with AB.
3. Draw another ray BY parallel to AX making an acute angle. Make sure the angle must be the same as considered in step 2. 4.Taking A as center draw an arc cutting at A1 on the line. Taking the same radius consider A1 as a center and draw another arc cutting line at A2. Repeat the same procedure and divide the line AX into 4 points A1, A2, A3, A4. In such a way, AA1=A1A2=A2A3=A3A4
4. Similar to step 4, Taking B as center draw an arc cutting at B1 on the line. Taking the same radius (set in step 4) consider B1 as a center and draw another arc cutting line at B2. Repeat the same procedure and divide the line BY into 5 points in such a way that BB1 = B1B2= B2B3= B3B4 = B4B5
5. Join A4B5
6. Line A4B5 intersects AB at a point P. Therefore, P is the point dividing the line segment AB internally in the ratio of 4: 5.

(ii) Steps of construction:

1. Draw a line segment AB = 7.6 cm.
2. Draw a ray AX making an acute angle at A with AB.
3. Draw another ray BY parallel to AX making an acute angle. Make sure the angle must be the same as considered in step 2.
4. Taking A as center draw an arc cutting at A1 on the line. Taking the same radius consider A1 as a center and draw another arc cutting line at A2. Repeat the same procedure and divide the line AX into 5 points A1, A2, A3, A4, and A5 In such a way, AA1 = A1A2 = A2A3 = A3A4 = A4A5
5. Similar to step 4, Taking B as center draw an arc cutting at B1 on the line. Taking the same radius (set in step 4) consider B1 as a center and draw another arc cutting line at B2.

Repeat the same procedure and divide the line BY into 8 points in such a way that BB1 = B1B2 = B2B3 = B3B4 = B4B5 = B5B6 = B6B7 = B7B8

1. Join A5B8
2. Line A5B8 intersect AB at a point P in the ratio 5:8
3. Measurement: PB = 4.7 cm and AP = 2.9 cm

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Draw a line segment of length 7.6 cm and divide it in the ratio 5: 8 . Measure the lengthin cm of the smallest part.A. 2.9

Solution

The correct option is A 2.9

Step 1: Draw a line segment AB of length 7.6 cm. Step 2: Draw a line segment AP (5+8=)13 cm long and divide it into AQ(5 cm) and QP(8 cm). Step 3: Join PB and draw a line QC parallel to PB so that it divides AB in the ratio 5:8.

On measuring the lengths, AC = 2.9 cm and CB = 4.7 cm

Text Solution

Solution : Step 1: Draw a line segment AB of length 7.6 cm using a ruler. <br> Step 2: Draw a ray AC having an acute angle with line AB. <br> Step 3: Mark 13 equidistant points on ray AC, `A_1,A_2,A_3 ,...,A _13` <br> Step 4: Join `A _13` to B <br> Step 5: Draw `A _5`P which should be parallel to `A_13`B. Point P divides AB in the ratio 5:8. <br>On measuring the lengths, we get AP=2.9 cm and PB=4.7 cm. <br> <img src="//d10lpgp6xz60nq.cloudfront.net/physics_images/X_C11_E01_001_S01.png" width="80%">

Construct a triangle with sides 5 cm, 6 cm and 7 cm and then another triangle whose sides arc

Steps of Construction :

(i)     Construct a ΔABC in which AB = 7cm, AC = 5 cm, BC = 6 cm.(ii)    At A draw an acute ΔBAX below base AB.

(iii)   Along AX, mark off 7 points A1, A2, A1,.,

(iv) Join A5B.
(v) From A7 draw A7B’ || A5B meeting produced part of AB at B’.(vi) From B’, draw B‘C’ || BC intersecting the extended line segment AC at C’.Thus, AB‘C’ is the required triangle each of whose sides is 7/5 of the corresponding sides of the triangle ΔABC.Justification :

Last updated at July 14, 2020 by

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