Does half as much work as B in three fourth of the time if together they take 18 days to complete the work how much time shall b take to do it?

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A does half as much work as B in three fourths of the time. If together they take 18 days to complete a work, how much time shall B take to do it?

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Given,

⇒ A × 1/6 = B × 1/2

⇒ A = 3B

⇒ \(\frac{A}{B} = \frac{3}{1}\)

∴ A’s efficiency = 3 unit / day.

& B’s efficiency = 1 unit / day.

According to Qs.

(A + B) Complete in 10 day

∴ Total Work = (3 + 1) × 10

= 4 × 10 = 40

∴ Time taken by \(A = \frac{{40}}{{3}}\)

= 13.33 Days = 13 Days.

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Correct Answer:

Description for Correct answer:

\( \Large A:B \)time \( \Large 3:1 \)eff. \( \Large 1:2 \)We have to do time equal so,

Both do the work in 18 days So, total work = \( \Large \left( A + B\right) 's eff. \times 18 \) = \( \Large \left( 4 + 6\right) \times 18 \) = 180 units. B will complete the work in

=\( \Large \frac{180}{6} =30\) days


Part of solved Time and work questions and answers : >> Aptitude >> Time and work

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