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The correct answer is 110 W.
Key Points
- The Power of the bulb is 110 W.
- Here the potential of the generator = 220 V
- Current flowing across the electric bulb I = 0.50 A
- Therefore Power of the bulb \(P = V * I\)
- \(P = 220 * 0.50 = 110 W\)
Additional Information
- Ohm's law equation (formula): V = I × R and the power-law equation (formula):
- I or J = international ampere, or intensity and R = resistance. V = voltage, electric potential difference Δ V or E = electromotive force (emf = voltage).
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Here, Ptential of the generator, V = 220 VCurrent flowing across the electric bulb, I = 0.50 ATherefore, Power of bulb, P = VI = 220 V x 0.50 A
= 110 W.
An electric bulb is connected to a 220 V generator the current is 0.50A What is the power of the bulb?
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