Text Solution
`167 V``100 V``625 V``250 V`
Answer : C
Solution : After charging, total charge on the capacitor `Q = CV` <br> `= 10 xx 10^(-6) F xx 1000 V = 10^(-2) C`. <br> Common potential `V = (C_(1)V_(1))/(C_(1) + C_(2)) = (10^(-2))/(16 xx 10^(-6)) = 625 V`.
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